For the output of a full-adder, what is the result when the conditions yield a Sum of 0 and a Carry of 1?

For the output of a full-adder, what is the result when the conditions yield a Sum of 0 and a Carry of 1?

• A. Sum = 1, Carry = 0
• B. Sum = 0, Carry = 1
• C. Sum = 1, Carry = 1
• D. Sum = 0, Carry = 0

Answer: (B)

In the context of a full-adder, which is a digital circuit that adds three bits (two significant bits and a carry-in bit), the outputs are defined as the Sum and the Carry. Specifically, the Sum represents the least significant bit of the addition result, while the Carry signifies whether there is a need to carry over a bit to the next higher significance. When you have a Sum of 0 and a Carry of 1, it indicates a specific condition in the addition process. The full-adder can produce this output when the combination of its inputs leads to a situation where the total value of the inputs exceeds the binary limit for a single digit, effectively meaning that although the Sum itself does not have a value (it is 0), there is a transition that necessitates carrying over to the next more significant bit. This scenario could occur, for instance, if two binary inputs are both 1 (which yields a 2 in decimal) and there is a carry-in of 0. The full-adder would then compute the addition as follows: 1 + 1 + 0 produces a Sum of 0 (because 2 in binary results in 10) with a Carry of 1 (the '1'

In the context of a full-adder, which is a digital circuit that adds three bits (two significant bits and a carry-in bit), the outputs are defined as the Sum and the Carry. Specifically, the Sum represents the least significant bit of the addition result, while the Carry signifies whether there is a need to carry over a bit to the next higher significance.

When you have a Sum of 0 and a Carry of 1, it indicates a specific condition in the addition process. The full-adder can produce this output when the combination of its inputs leads to a situation where the total value of the inputs exceeds the binary limit for a single digit, effectively meaning that although the Sum itself does not have a value (it is 0), there is a transition that necessitates carrying over to the next more significant bit.

This scenario could occur, for instance, if two binary inputs are both 1 (which yields a 2 in decimal) and there is a carry-in of 0. The full-adder would then compute the addition as follows: 1 + 1 + 0 produces a Sum of 0 (because 2 in binary results in 10) with a Carry of 1 (the '1'